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Vb = Ve + 0.7 Volts Vb is calculated by the voltage dividor created by the two resistors R2 and R3. Calculating, you have Vb = (6 Volts * 4.7 kOhms) / (10 + 4.7 kOhms) = 1.92 Volts and hence Ve = 1.92 - 0.7 = 1.22 Volts. Calculating the emitter current with Ohm's Law Ie = Ve / R4 = 1.22 Volts / 47 Ohms = 25.96 mA From the schematic, the emitter and collector currents are approximately equal Ic = Ie = 25.96 mA. As such the power now can be calculated since Vce = 6 - 1.22 = 4.78 Volts and P = Ic * Vce = 25.96 mA * 4.78 V = 124 mW  JK^_`a0123\]pqrs45HIJKPQdtkjs CJEHUj(pK@ CJUVaJjCJEHUjoK@ CJUVaJjCJUmHnHujCJEHUjmK@ CJUVaJjCJEHUjmK@ CJUVaJjCJEHUjsmK@ CJUVaJjCJEHUjlK@ CJUVaJ jCJUCJ*OPh$a$ defg    ࿶ડ jUj&CJEHUjpK@ CJUVaJjNCJEHUjpK@ CJUVaJjw CJEHUjrpK@ CJUVaJCJ jCJUjJ CJEHUj|oK@ CJUVaJhiIz{|} ]^P  1h/ =!"#$%DdhJ  C A? "2@qXDp`!qXf@xt|xڅPQssIl$Qm:@#~-6X$$TjZOQ׹Ǫ&̝\Bp.ؓg;,J1FUi3%tE252%`7rO}pi[FD7G /D9pI.q!G8&σxz -^{jp0]91ǻ:fs}= >8DdhJ  C A? 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